Stan Moody Upsets John Higgins in British Open Knockout

In a surprising turn of events at the British Open, 19-year-old Stan Moody defeated four-time champion John Higgins 4-2 in the last 16, marking a significant achievement in his budding snooker career.

Moody, who hails from Halifax, showcased his talent by taking early leads of 1-0 and 2-1. However, Higgins, aged 51, managed to level the score on both occasions, demonstrating his experience and skill.

The decisive moment came when Moody made a break of 46 to pull ahead 3-2. He then sealed the match with a clearance of 69 in the sixth frame, overcoming a 61-0 deficit to secure his victory.

With this win, Moody progresses to the quarter-finals, where he will face fellow Englishman Liam Highfield. This marks Moody's second consecutive year reaching this stage in the tournament, highlighting his growing prominence in the sport.

In other matches, Judd Trump advanced with a commanding 4-0 win over David Gilbert, while Jack Lisowski defeated Lyu Haotian 4-1. Mark Selby also moved forward by overcoming Iulian Boiko 4-2, setting up an exciting quarter-final round.